ch3coona naoh cao

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The correct option is C

${\mathrm{CH}}_4$

Explanation:

(C) When sodium acetate $\left({\mathrm{CH}}_3\mathrm{COONa}\right)$ reacts with sodium hydroxide $\left(\mathrm{NaOH}\right)$ in the presence of calcium oxide $\left(\mathrm{CaO}\right)$, methane $\left({\mathrm{CH}}_4\right)$ gas is obtained along with sodium carbonate $\left({\mathrm{Na}}_2{\mathrm{CO}}_3\right)$.

The chemical equation is as follows:

• ${\mathrm{CH}}_3\mathrm{COONa}+\mathrm{NaOH}\stackrel{\mathrm{CaO}}{\to }{\mathrm{CH}}_4+{\mathrm{Na}}_2{\mathrm{CO}}_3$

Final Answer:

Hence, the correct option is (C) i.e. ${\mathrm{CH}}_4$.

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