To balance the equation C2H5COOCH3 + NaOH = C2H5O2Na using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.
Step 1: Label Each Compound With a Variable
Label each compound (reactant or product) in the equation with a variable đồ sộ represent the unknown coefficients.
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a C2H5COOCH3 + b NaOH = c C2H5O2Na
Step 2: Create a System of Equations
Create an equation for each element (C, H, O, Na) where each term represents the number of atoms of the element in each reactant or product.
C: 4a + 0b = 2c H: 8a + 1b = 5c O: 2a + 1b = 2c Na: 0a + 1b = 1c
Step 3: Solve For All Variables
Use substitution, Gaussian elimination, or a calculator đồ sộ solve for each variable.
- 4a - 2c = 0
- 8a + 1b - 5c = 0
- 2a + 1b - 2c = 0
- 1b - 1c = 0
Use your graphing calculator's rref() function (or an online rref calculator) đồ sộ convert the following matrix into reduced row-echelon-form:
[ 4 0 -2 0] [ 8 1 -5 0] [ 2 1 -2 0] [ 0 1 -1 0]
The resulting matrix can be used đồ sộ determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.
Simplify the result đồ sộ get the lowest, whole integer values.
- a = 1 (C2H5COOCH3)
- b = 2 (NaOH)
- c = 2 (C2H5O2Na)
Step 4: Substitute Coefficients and Verify Result
Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.
C2H5COOCH3 + 2 NaOH = 2 C2H5O2Na
Since there is an equal number of each element in the reactants and products of C2H5COOCH3 + 2NaOH = 2C2H5O2Na, the equation is balanced.
The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the over of a chemical reaction as at the beginning. To be balanced, every element in C2H5COOCH3 + NaOH = C2H5O2Na must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used đồ sộ balance one element at a time until both sides are equal and the chemical equation is balanced.
Step 1: Count the number of each element on the left and right hand sides
|Reactants (Left Hand Side)||Products (Right Hand Side)|
Step 2: Multiply coefficients for compounds đồ sộ balance out each element
For each element that is not equal, try đồ sộ balance it by adding more of it đồ sộ the side with less. Sometimes there may be multiple compounds with that element on one side, ví you'll need đồ sộ use your best judgement and be prepared đồ sộ go back and try the other options.
C is not balanced. Add 1 molecule of C2H5O2Na đồ sộ the product (right-hand) side đồ sộ balance Carbon:
C2H5COOCH3 + NaOH = 2C2H5O2Na
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Reactants Products C 4 4 ✔️ H 9 10 ❌ O 3 4 ❌ Na 1 2 ❌
H is not balanced. Add 1 molecule of NaOH đồ sộ the reactant (left-hand) side đồ sộ balance Hydrogen:
C2H5COOCH3 + 2NaOH = 2C2H5O2Na
Reactants Products C 4 4 ✔️ H 10 10 ✔️ O 4 4 ✔️ Na 2 2 ✔️
Step 3: Verify that the equation is balanced
Since there are an equal number of atoms of each element on both sides, the equation is balanced.
C2H5COOCH3 + 2NaOH = 2C2H5O2Na